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Cambridge Veritas

UNIT 02 / Linear Equations

Equations with No Solution

A false constant statement after valid simplification shows that no input can satisfy the equation. Explain the contradiction.

5 worked examples 4 questions + written practice TEKS alignedGo to practice
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By · Algebra I learning resources

Introduction

Equations with No Solution helps you connect a mathematical rule to a result you can explain and check. A false constant statement after valid simplification shows that no input can satisfy the equation. Explain the contradiction. This lesson belongs to linear equations and builds toward independent Algebra I problem solving.

A.5A · Readiness

Alignment uses 19 TAC §111.39(c). Review lessons sample their listed standards. Readiness and supporting labels describe STAAR emphasis, not whether a topic is required.

Learning objectives

  • Identify the quantities and representations used in equations with no solution.
  • Apply the lesson's rule to solve a numerical or contextual problem.
  • Explain each mathematical step using the correct vocabulary.
  • Verify an answer and correct a likely error.

Prerequisite knowledge

Use distribution, signed arithmetic, and inverse operations.

Previous lesson: Real-World Linear Equation Problems

Key mathematical vocabulary

variable
A letter representing an unknown or changing quantity.
constant
A value fixed within a problem.
expression
A mathematical phrase representing a value.
equation
A statement that two expressions are equal.
solution
A value making the original conditions true.

Formulas and rules

  • a(b+c)=ab+ac
  • Equivalent expressions agree for all allowed inputs.
  • A solution satisfies every original condition.

Preserve equality while solving

A false constant statement after valid simplification shows that no input can satisfy the equation. Explain the contradiction.

An equation states that two expressions have the same value. A solution is an input that makes the original statement true. Adding, subtracting, or multiplying both sides by the same number preserves equality; division is permitted only by a nonzero number.

First remove grouping symbols and combine like terms if needed. Gather variable terms on one side and constants on the other, then isolate the variable. An equation can have one solution, no solution, or infinitely many solutions. A false constant statement means no solution; a true identity means all permitted inputs work.

A method you can explain

  1. Read the question and identify the known information, unknown quantities, and any domain restrictions. Select a suitable representation and tool.
  2. Apply the relationship explained above. Distribute: 12x+240=12x+241.
  3. Write each calculation or logical inference on a separate line. Keep units and signs visible. When two methods are possible, compare which one uses the given information most directly.
  4. Check the result in the ORIGINAL conditions, not merely the last simplified line. The constant comparison determines whether the equation is a contradiction or identity.
  5. Interpret what the answer means. Decide whether its size, sign, and precision make sense; identify a restriction or assumption that would change the conclusion.

Five worked examples

Example 1 · Beginner

Solve 12(x + 20) = 12x + 241.

  1. Distribute: 12x+240=12x+241.
  2. Subtract 12x: 240=241.
  3. This false statement cannot hold for any x. The solution set is empty.

Answer: No solution

Verify: The constant comparison determines whether the equation is a contradiction or identity.

Avoid this mistake: Changing only one side: apply each operation to both sides.

Example 2 · Basic

Solve 13(x + 20) = 13x + 261.

  1. Distribute: 13x+260=13x+261.
  2. Subtract 13x: 260=261.
  3. This false statement cannot hold for any x. The solution set is empty.

Answer: No solution

Verify: The constant comparison determines whether the equation is a contradiction or identity.

Avoid this mistake: Dropping a negative coefficient during division.

Example 3 · Intermediate

Solve 14(x + 20) = 14x + 281.

  1. Distribute: 14x+280=14x+281.
  2. Subtract 14x: 280=281.
  3. This false statement cannot hold for any x. The solution set is empty.

Answer: No solution

Verify: The constant comparison determines whether the equation is a contradiction or identity.

Avoid this mistake: Assuming every equation has one numerical solution: inspect identities and contradictions.

Example 4 · Advanced

Solve 2(x + 21) = 2x + 43.

  1. Distribute: 2x+42=2x+43.
  2. Subtract 2x: 42=43.
  3. This false statement cannot hold for any x. The solution set is empty.

Answer: No solution

Verify: The constant comparison determines whether the equation is a contradiction or identity.

Avoid this mistake: Changing only one side: apply each operation to both sides.

Example 5 · Challenge

Solve 3(x + 21) = 3x + 64.

  1. Distribute: 3x+63=3x+64.
  2. Subtract 3x: 63=64.
  3. This false statement cannot hold for any x. The solution set is empty.

Answer: No solution

Verify: The constant comparison determines whether the equation is a contradiction or identity.

Avoid this mistake: Dropping a negative coefficient during division.

Common mistakes and corrections

  • Changing only one side: apply each operation to both sides.
  • Dropping a negative coefficient during division.
  • Assuming every equation has one numerical solution: inspect identities and contradictions.

Real-world applications

  1. Find hours worked from a fixed fee and hourly charge. Define the input and its units, apply the mathematical relationship, and check that the result fits the setting.
  2. Determine the quantity of supplies affordable at a known total cost. Define the input and its units, apply the mathematical relationship, and check that the result fits the setting.

Topic summary

A false constant statement after valid simplification shows that no input can satisfy the equation. Explain the contradiction.

An equation states that two expressions have the same value. A solution is an input that makes the original statement true. Adding, subtracting, or multiplying both sides by the same number preserves equality; division is permitted only by a nonzero number.

Frequently asked questions

What should I know before equations with no solution?

Use distribution, signed arithmetic, and inverse operations.

How can I check my work?

The constant comparison determines whether the equation is a contradiction or identity. A numerical check can detect an error; when claiming an identity for all inputs, also explain the algebraic property that makes it true.

Which mistakes should I watch for?

Changing only one side: apply each operation to both sides. Dropping a negative coefficient during division. Assuming every equation has one numerical solution: inspect identities and contradictions.

Can I use another valid method?

Yes. Explain your assumptions, show enough intermediate work to justify the result, and verify it in the original problem. Equivalent expressions and valid alternative methods receive credit.

Mathematical process practice · A.1A–A.1G
  • A.1A: Find hours worked from a fixed fee and hourly charge.
  • A.1B: Plan, solve, check, and interpret the written response.
  • A.1C: Select paper, a calculator, a table, or a graph; explain the choice.
  • A.1D: Connect symbols with a verbal explanation and another representation.
  • A.1E: Organize the solution with a table, diagram, or labeled equations.
  • A.1F: Explain how the representation and the algebraic rule express the same relationship.
  • A.1G: Justify each operation and the reasonableness of the conclusion.

Quick revision notes

  • A false constant statement after valid simplification shows that no input can satisfy the equation. Explain the contradiction.
  • Changing only one side: apply each operation to both sides.
  • Dropping a negative coefficient during division.
  • Assuming every equation has one numerical solution: inspect identities and contradictions.
Practice for STAAR EOC ? My learning dashboard

Practice and explain

Try all four multiple-choice questions, then show your reasoning in the written response. Objective scores and AI feedback assess different skills.

Checking your practice access…

Part A: Four objective questions

Question 1

Solve 4(x + 21) = 4x + 85.

Question 2

Solve 5(x + 21) = 5x + 106.

Question 3

Solve 6(x + 21) = 6x + 127.

Question 4

Solve 7(x + 21) = 7x + 148.

Part B: Explain your reasoning

Solve 8(x + 21) = 8x + 169. Show your complete working. Define the quantities, select and explain a suitable method or tool, organize a table, diagram, or symbolic representation, and connect it to your result. Verify the result against the original conditions and explain any restrictions or contextual meaning.

concept understanding
2 marks
mathematical method
3 marks
calculation accuracy
3 marks
reasoning
2 marks

Show your steps and explain how you checked your answer.

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Original Cambridge Veritas practice. These are not official STAAR items. Cambridge Veritas is not affiliated with or endorsed by TEA.

Official Algebra I TEKS (§111.39) · TEA assessed curriculum · STAAR blueprint · TEA instructional materials