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Cambridge Veritas
Algebra 1 learning resource 10 min read

Solving Linear Equations Worksheet With Answers

Solve a graduated set of linear equations, justify inverse operations and check every answer by substitution.

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What you will be able to do

  • Work each problem without looking at the answer.
  • Write the algebraic step that justifies each change.
  • Check the result in the original relationship.
  • Use the error notes to decide what to practise next.

How to use this worksheet

Solve in order. Keep both sides balanced, combine like terms before isolating the variable and substitute the result into the original equation.

  • Undo operations in reverse order
  • Distribute and combine like terms
  • Handle variables on both sides
  • Recognise no-solution and infinitely-many-solution equations

For a clean student copy, print this page and cover the worked solutions or select the problem pages in your browser’s print preview.

Practice problems

Problem 1

x + 7 = 19

Problem 2

5x = -35

Problem 3

3x - 8 = 16

Problem 4

4(x - 2) + 3 = 19

Problem 5

7x + 4 = 3x + 28

Problem 6

2(3x + 1) = 6x + 5

Answer key with worked solutions

Problem 1

x + 7 = 19

  1. 1.Subtract 7 from both sides: x = 12.

Answer: x = 12

Check: 12 + 7 = 19.

Problem 2

5x = -35

  1. 1.Divide both sides by 5: x = -7.

Answer: x = -7

Check: 5(-7) = -35.

Problem 3

3x - 8 = 16

  1. 1.Add 8: 3x = 24.
  2. 2.Divide by 3: x = 8.

Answer: x = 8

Check: 3(8) - 8 = 16.

Problem 4

4(x - 2) + 3 = 19

  1. 1.Distribute: 4x - 8 + 3 = 19.
  2. 2.Combine: 4x - 5 = 19.
  3. 3.Add 5 and divide by 4: x = 6.

Answer: x = 6

Check: 4(6 - 2) + 3 = 19.

Problem 5

7x + 4 = 3x + 28

  1. 1.Subtract 3x: 4x + 4 = 28.
  2. 2.Subtract 4: 4x = 24.
  3. 3.Divide by 4: x = 6.

Answer: x = 6

Check: 46 = 46.

Problem 6

2(3x + 1) = 6x + 5

  1. 1.Distribute: 6x + 2 = 6x + 5.
  2. 2.Subtract 6x: 2 = 5, a contradiction.

Answer: No solution

Check: The variable terms cancel and leave a false statement.

Use mistakes to choose the next step

Read why equations feel difficultPractise linear inequalities next

If this happenedLikely issueNext practice move
Sign changed incorrectlyInverse operation or negative-number errorWrite the same operation on both sides
Distribution missed a termParentheses errorDraw arrows from the multiplier to every term
Answer works in simplified line but not originalEarlier algebra errorSubstitute into the original equation
Variable disappearsIdentity or contradictionDecide whether the remaining statement is always true or false

When independent practice is not enough

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Useful answers

Frequently asked questions

How can I check a linear-equation answer?

Substitute the value into the original equation and confirm that both sides are equal.

Why do operations have to be done to both sides?

An equation states that two expressions are equal. Applying the same valid operation preserves that equality.

These answers are visible for readers. FAQ rich-result markup is intentionally not used because Google retired that search feature in 2026.

Sources, scope and accuracy

The worked examples and practice questions on this page are original Cambridge Veritas learning materials, not released STAAR items. Curriculum and testing details can change; use the linked Texas Education Agency pages for current official information. Cambridge Veritas is not affiliated with or endorsed by TEA.

Linear Equations Worksheet With Answers